5(2-n)-2(n-5)=2-5(2-n)

Solution for 5(2-n)-2(n-5)=2-5(2-n) equation:

5(2-n)-2(n-5)=2-5(2-n)

We move all terms to the left:

5(2-n)-2(n-5)-(2-5(2-n))=0

We add all the numbers together, and all the variables

5(-1n+2)-2(n-5)-(2-5(-1n+2))=0

We multiply parentheses

-5n-2n-(2-5(-1n+2))+10+10=0


We calculate terms in parentheses: -(2-5(-1n+2)), so:

2-5(-1n+2)

determiningTheFunctionDomain
-5(-1n+2)+2

We multiply parentheses

5n-10+2

We add all the numbers together, and all the variables

5n-8

Back to the equation:

-(5n-8)


We add all the numbers together, and all the variables

-7n-(5n-8)+20=0

We get rid of parentheses

-7n-5n+8+20=0

We add all the numbers together, and all the variables

-12n+28=0

We move all terms containing n to the left, all other terms to the right

-12n=-28

n=-28/-12

n=2+1/3