10x-(3x-1)=4(x+5)-12

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Solution for 10x-(3x-1)=4(x+5)-12 equation: 



10x-(3x-1)=4(x+5)-12

We move all terms to the left:

10x-(3x-1)-(4(x+5)-12)=0

We get rid of parentheses

10x-3x-(4(x+5)-12)+1=0



We calculate terms in parentheses: -(4(x+5)-12), so:

4(x+5)-12

We multiply parentheses

4x+20-12

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

7x-(4x+8)+1=0

We get rid of parentheses

7x-4x-8+1=0

We add all the numbers together, and all the variables

3x-7=0

We move all terms containing x to the left, all other terms to the right

3x=7

x=7/3

x=2+1/3

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