3x(2-x)=2-(x-8)+2x

Solution for 3x(2-x)=2-(x-8)+2x equation:

3x(2-x)=2-(x-8)+2x

We move all terms to the left:

3x(2-x)-(2-(x-8)+2x)=0

We add all the numbers together, and all the variables

3x(-1x+2)-(2-(x-8)+2x)=0

We multiply parentheses

-3x^2+6x-(2-(x-8)+2x)=0


We calculate terms in parentheses: -(2-(x-8)+2x), so:

2-(x-8)+2x

determiningTheFunctionDomain
-(x-8)+2x+2

We add all the numbers together, and all the variables

2x-(x-8)+2

We get rid of parentheses

2x-x+8+2

We add all the numbers together, and all the variables

x+10

Back to the equation:

-(x+10)


We get rid of parentheses

-3x^2+6x-x-10=0

We add all the numbers together, and all the variables

-3x^2+5x-10=0

a = -3; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·(-3)·(-10)
Δ = -95
Delta is less than zero, so there is no solution for the equation