5(2+3m)=-(6+m)

Solution for 5(2+3m)=-(6+m) equation:

5(2+3m)=-(6+m)

We move all terms to the left:

5(2+3m)-(-(6+m))=0

We add all the numbers together, and all the variables

5(3m+2)-(-(m+6))=0

We multiply parentheses

15m-(-(m+6))+10=0


We calculate terms in parentheses: -(-(m+6)), so:

-(m+6)

We get rid of parentheses

-m-6

We add all the numbers together, and all the variables

-1m-6

Back to the equation:

-(-1m-6)


We get rid of parentheses

15m+1m+6+10=0

We add all the numbers together, and all the variables

16m+16=0

We move all terms containing m to the left, all other terms to the right

16m=-16

m=-16/16

m=-1