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4(3x+1)=6(2x-1)+5
We move all terms to the left:
4(3x+1)-(6(2x-1)+5)=0
We multiply parentheses
12x-(6(2x-1)+5)+4=0
We calculate terms in parentheses: -(6(2x-1)+5), so:We get rid of parentheses
6(2x-1)+5
We multiply parentheses
12x-6+5
We add all the numbers together, and all the variables
12x-1
Back to the equation:
-(12x-1)
12x-12x+1+4=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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