-3x(2x+4)+3x=4(x+4)

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Solution for -3x(2x+4)+3x=4(x+4) equation: 



-3x(2x+4)+3x=4(x+4)

We move all terms to the left:

-3x(2x+4)+3x-(4(x+4))=0

We add all the numbers together, and all the variables

3x-3x(2x+4)-(4(x+4))=0

We multiply parentheses

-6x^2+3x-12x-(4(x+4))=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

-6x^2-9x-(4x+16)=0

We get rid of parentheses

-6x^2-9x-4x-16=0

We add all the numbers together, and all the variables

-6x^2-13x-16=0

a = -6; b = -13; c = -16;
Δ = b2-4ac
Δ = -132-4·(-6)·(-16)
Δ = -215
Delta is less than zero, so there is no solution for the equation

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