23+8x=(2x-12)+10(x+10)

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Solution for 23+8x=(2x-12)+10(x+10) equation: 



23+8x=(2x-12)+10(x+10)

We move all terms to the left:

23+8x-((2x-12)+10(x+10))=0



We calculate terms in parentheses: -((2x-12)+10(x+10)), so:

(2x-12)+10(x+10)

We multiply parentheses

(2x-12)+10x+100

We get rid of parentheses

2x+10x-12+100

We add all the numbers together, and all the variables

12x+88

Back to the equation:

-(12x+88)



We get rid of parentheses

8x-12x-88+23=0

We add all the numbers together, and all the variables

-4x-65=0

We move all terms containing x to the left, all other terms to the right

-4x=65

x=65/-4

x=-16+1/4

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