5(10-3b)=105-7b+4(11-4b)

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Solution for 5(10-3b)=105-7b+4(11-4b) equation: 



5(10-3b)=105-7b+4(11-4b)

We move all terms to the left:

5(10-3b)-(105-7b+4(11-4b))=0

We add all the numbers together, and all the variables

5(-3b+10)-(105-7b+4(-4b+11))=0

We multiply parentheses

-15b-(105-7b+4(-4b+11))+50=0



We calculate terms in parentheses: -(105-7b+4(-4b+11)), so:

105-7b+4(-4b+11)

determiningTheFunctionDomain
-7b+4(-4b+11)+105

We multiply parentheses

-7b-16b+44+105

We add all the numbers together, and all the variables

-23b+149

Back to the equation:

-(-23b+149)



We get rid of parentheses

-15b+23b-149+50=0

We add all the numbers together, and all the variables

8b-99=0

We move all terms containing b to the left, all other terms to the right

8b=99

b=99/8

b=12+3/8

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