x(4x+3)=2x-5(3-x)+2

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Solution for x(4x+3)=2x-5(3-x)+2 equation: 



x(4x+3)=2x-5(3-x)+2

We move all terms to the left:

x(4x+3)-(2x-5(3-x)+2)=0

We add all the numbers together, and all the variables

x(4x+3)-(2x-5(-1x+3)+2)=0

We multiply parentheses

4x^2+3x-(2x-5(-1x+3)+2)=0



We calculate terms in parentheses: -(2x-5(-1x+3)+2), so:

2x-5(-1x+3)+2

We multiply parentheses

2x+5x-15+2

We add all the numbers together, and all the variables

7x-13

Back to the equation:

-(7x-13)



We get rid of parentheses

4x^2+3x-7x+13=0

We add all the numbers together, and all the variables

4x^2-4x+13=0

a = 4; b = -4; c = +13;
Δ = b2-4ac
Δ = -42-4·4·13
Δ = -192
Delta is less than zero, so there is no solution for the equation

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