5(y-3)=(y-2)+19

Solution for 5(y-3)=(y-2)+19 equation:

5(y-3)=(y-2)+19

We move all terms to the left:

5(y-3)-((y-2)+19)=0

We multiply parentheses

5y-((y-2)+19)-15=0


We calculate terms in parentheses: -((y-2)+19), so:

(y-2)+19

We get rid of parentheses

y-2+19

We add all the numbers together, and all the variables

y+17

Back to the equation:

-(y+17)


We get rid of parentheses

5y-y-17-15=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8