5(1-4z+1)=-3(3z-1)+1

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Solution for 5(1-4z+1)=-3(3z-1)+1 equation: 



5(1-4z+1)=-3(3z-1)+1

We move all terms to the left:

5(1-4z+1)-(-3(3z-1)+1)=0

We add all the numbers together, and all the variables

5(-4z+2)-(-3(3z-1)+1)=0

We multiply parentheses

-20z-(-3(3z-1)+1)+10=0



We calculate terms in parentheses: -(-3(3z-1)+1), so:

-3(3z-1)+1

We multiply parentheses

-9z+3+1

We add all the numbers together, and all the variables

-9z+4

Back to the equation:

-(-9z+4)



We get rid of parentheses

-20z+9z-4+10=0

We add all the numbers together, and all the variables

-11z+6=0

We move all terms containing z to the left, all other terms to the right

-11z=-6

z=-6/-11

z=6/11

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