2/3(3x+9)=-1/4(2x+8)

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Solution for 2/3(3x+9)=-1/4(2x+8) equation:



2/3(3x+9)=-1/4(2x+8)
We move all terms to the left:
2/3(3x+9)-(-1/4(2x+8))=0
Domain of the equation: 3(3x+9)!=0
x∈R
Domain of the equation: 4(2x+8))!=0
x∈R
We calculate fractions
(8x2/(3(3x+9)*4(2x+8)))+(-(-3x3)/(3(3x+9)*4(2x+8)))=0
We calculate terms in parentheses: +(8x2/(3(3x+9)*4(2x+8))), so:
8x2/(3(3x+9)*4(2x+8))
We multiply all the terms by the denominator
8x2
We add all the numbers together, and all the variables
8x^2
Back to the equation:
+(8x^2)
We calculate terms in parentheses: +(-(-3x3)/(3(3x+9)*4(2x+8))), so:
-(-3x3)/(3(3x+9)*4(2x+8))
We add all the numbers together, and all the variables
-(-3x^3)/(3(3x+9)*4(2x+8))
We multiply all the terms by the denominator
-(-3x^3)
We do not support expression: x^3

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