5(1+-5x)+5(-8x+-2)=-4x+-8x(1*5+-5x*5)+5(-8x+-2)=-4x+-8x(5+-25x)+5(-8x+-2)=-4x+-8x

Solution for 5(1+-5x)+5(-8x+-2)=-4x+-8x(1*5+-5x*5)+5(-8x+-2)=-4x+-8x(5+-25x)+5(-8x+-2)=-4x+-8x equation:

5(1+-5x)+5(-8x+-2)=-4x+-8x(1*5+-5x*5)+5(-8x+-2)=-4x+-8x(5+-25x)+5(-8x+-2)=-4x+-8x

We move all terms to the left:

5(1+-5x)+5(-8x+-2)-(-4x+-8x(1*5+-5x*5)+5(-8x+-2))=0

We add all the numbers together, and all the variables

5(-5x)+5(-8x-2)-(-4x+-8x(-5x*5)+5(-8x-2))=0

We use the square of the difference formula

5(-5x)+5(-8x-2)-(-4x-8x(-5x*5)+5(-8x-2))=0

We multiply parentheses

-25x-40x-(-4x-8x(-5x*5)+5(-8x-2))-10=0


We calculate terms in parentheses: -(-4x-8x(-5x*5)+5(-8x-2)), so:

-4x-8x(-5x*5)+5(-8x-2)

We multiply parentheses

200x^2-4x-40x-10

We add all the numbers together, and all the variables

200x^2-44x-10

Back to the equation:

-(200x^2-44x-10)


We add all the numbers together, and all the variables

-65x-(200x^2-44x-10)-10=0

We get rid of parentheses

-200x^2-65x+44x+10-10=0

We add all the numbers together, and all the variables

-200x^2-21x=0

a = -200; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·(-200)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*-200}=\frac{0}{-400}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*-200}=\frac{42}{-400}
=-21/200
$