4(3-x)+8(x+1)=32

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Solution for 4(3-x)+8(x+1)=32 equation: 



4(3-x)+8(x+1)=32

We move all terms to the left:

4(3-x)+8(x+1)-(32)=0

We add all the numbers together, and all the variables

4(-1x+3)+8(x+1)-32=0

We multiply parentheses

-4x+8x+12+8-32=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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