4x-2+6x=3(2x-4)+8-2x

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Solution for 4x-2+6x=3(2x-4)+8-2x equation:



4x-2+6x=3(2x-4)+8-2x
We move all terms to the left:
4x-2+6x-(3(2x-4)+8-2x)=0
We add all the numbers together, and all the variables
10x-(3(2x-4)+8-2x)-2=0
We calculate terms in parentheses: -(3(2x-4)+8-2x), so:
3(2x-4)+8-2x
determiningTheFunctionDomain 3(2x-4)-2x+8
We add all the numbers together, and all the variables
-2x+3(2x-4)+8
We multiply parentheses
-2x+6x-12+8
We add all the numbers together, and all the variables
4x-4
Back to the equation:
-(4x-4)
We get rid of parentheses
10x-4x+4-2=0
We add all the numbers together, and all the variables
6x+2=0
We move all terms containing x to the left, all other terms to the right
6x=-2
x=-2/6
x=-1/3

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