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16+10+(x-10)=5+(x-5)+(x-4)
We move all terms to the left:
16+10+(x-10)-(5+(x-5)+(x-4))=0
We add all the numbers together, and all the variables
(x-10)-(5+(x-5)+(x-4))+26=0
We get rid of parentheses
x-(5+(x-5)+(x-4))-10+26=0
We calculate terms in parentheses: -(5+(x-5)+(x-4)), so:We add all the numbers together, and all the variables
5+(x-5)+(x-4)
determiningTheFunctionDomain (x-5)+(x-4)+5
We get rid of parentheses
x+x-5-4+5
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
x-(2x-4)+16=0
We get rid of parentheses
x-2x+4+16=0
We add all the numbers together, and all the variables
-1x+20=0
We move all terms containing x to the left, all other terms to the right
-x=-20
x=-20/-1
x=+20
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