5(-q-19)=10q+8(-2q+12)

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Solution for 5(-q-19)=10q+8(-2q+12) equation: 



5(-q-19)=10q+8(-2q+12)

We move all terms to the left:

5(-q-19)-(10q+8(-2q+12))=0

We add all the numbers together, and all the variables

5(-1q-19)-(10q+8(-2q+12))=0

We multiply parentheses

-5q-(10q+8(-2q+12))-95=0



We calculate terms in parentheses: -(10q+8(-2q+12)), so:

10q+8(-2q+12)

We multiply parentheses

10q-16q+96

We add all the numbers together, and all the variables

-6q+96

Back to the equation:

-(-6q+96)



We get rid of parentheses

-5q+6q-96-95=0

We add all the numbers together, and all the variables

q-191=0

We move all terms containing q to the left, all other terms to the right

q=191

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