5(2x-7)=3(3x+4)+15

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Solution for 5(2x-7)=3(3x+4)+15 equation: 



5(2x-7)=3(3x+4)+15

We move all terms to the left:

5(2x-7)-(3(3x+4)+15)=0

We multiply parentheses

10x-(3(3x+4)+15)-35=0



We calculate terms in parentheses: -(3(3x+4)+15), so:

3(3x+4)+15

We multiply parentheses

9x+12+15

We add all the numbers together, and all the variables

9x+27

Back to the equation:

-(9x+27)



We get rid of parentheses

10x-9x-27-35=0

We add all the numbers together, and all the variables

x-62=0

We move all terms containing x to the left, all other terms to the right

x=62

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