4z+9+(2z)=129

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Solution for 4z+9+(2z)=129 equation: 



4z+9+(2z)=129

We move all terms to the left:

4z+9+(2z)-(129)=0

We add all the numbers together, and all the variables

6z-120=0

We move all terms containing z to the left, all other terms to the right

6z=120

z=120/6

z=20

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