10x-2(4x-3)=-5(x+1)+13

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Solution for 10x-2(4x-3)=-5(x+1)+13 equation: 



10x-2(4x-3)=-5(x+1)+13

We move all terms to the left:

10x-2(4x-3)-(-5(x+1)+13)=0

We multiply parentheses

10x-8x-(-5(x+1)+13)+6=0



We calculate terms in parentheses: -(-5(x+1)+13), so:

-5(x+1)+13

We multiply parentheses

-5x-5+13

We add all the numbers together, and all the variables

-5x+8

Back to the equation:

-(-5x+8)



We add all the numbers together, and all the variables

2x-(-5x+8)+6=0

We get rid of parentheses

2x+5x-8+6=0

We add all the numbers together, and all the variables

7x-2=0

We move all terms containing x to the left, all other terms to the right

7x=2

x=2/7

x=2/7

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