3(r-4)+7=-11

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Solution for 3(r-4)+7=-11 equation: 



3(r-4)+7=-11

We move all terms to the left:

3(r-4)+7-(-11)=0

We add all the numbers together, and all the variables

3(r-4)+18=0

We multiply parentheses

3r-12+18=0

We add all the numbers together, and all the variables

3r+6=0

We move all terms containing r to the left, all other terms to the right

3r=-6

r=-6/3

r=-2

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