4y-2=1-(2y+3)

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Solution for 4y-2=1-(2y+3) equation: 



4y-2=1-(2y+3)

We move all terms to the left:

4y-2-(1-(2y+3))=0



We calculate terms in parentheses: -(1-(2y+3)), so:

1-(2y+3)

determiningTheFunctionDomain
-(2y+3)+1

We get rid of parentheses

-2y-3+1

We add all the numbers together, and all the variables

-2y-2

Back to the equation:

-(-2y-2)



We get rid of parentheses

4y+2y+2-2=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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