4(6-x)=2(x+1)+2(x+1)+x+x

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Solution for 4(6-x)=2(x+1)+2(x+1)+x+x equation: 



4(6-x)=2(x+1)+2(x+1)+x+x

We move all terms to the left:

4(6-x)-(2(x+1)+2(x+1)+x+x)=0

We add all the numbers together, and all the variables

4(-1x+6)-(2(x+1)+2(x+1)+x+x)=0

We multiply parentheses

-4x-(2(x+1)+2(x+1)+x+x)+24=0



We calculate terms in parentheses: -(2(x+1)+2(x+1)+x+x), so:

2(x+1)+2(x+1)+x+x

We add all the numbers together, and all the variables

2x+2(x+1)+2(x+1)

We multiply parentheses

2x+2x+2x+2+2

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

-4x-6x-4+24=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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