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4x^2=20x-25
We move all terms to the left:
4x^2-(20x-25)=0
We get rid of parentheses
4x^2-20x+25=0
a = 4; b = -20; c = +25;
Δ = b2-4ac
Δ = -202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{8}=2+1/2$
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