-(4/7)n=-16

Solution for -(4/7)n=-16 equation:

-(4/7)n=-16

We move all terms to the left:

-(4/7)n-(-16)=0


Domain of the equation: 7)n!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

-(+4/7)n-(-16)=0

We add all the numbers together, and all the variables

-(+4/7)n+16=0

We multiply parentheses

-4n^2+16=0

a = -4; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-4)·16
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-4}=\frac{-16}{-8}
=+2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-4}=\frac{16}{-8}
=-2
$