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4x^2-972=0
a = 4; b = 0; c = -972;
Δ = b2-4ac
Δ = 02-4·4·(-972)
Δ = 15552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15552}=\sqrt{5184*3}=\sqrt{5184}*\sqrt{3}=72\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72\sqrt{3}}{2*4}=\frac{0-72\sqrt{3}}{8} =-\frac{72\sqrt{3}}{8} =-9\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72\sqrt{3}}{2*4}=\frac{0+72\sqrt{3}}{8} =\frac{72\sqrt{3}}{8} =9\sqrt{3} $
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