230=(2x)+x+(x-20)

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Solution for 230=(2x)+x+(x-20) equation:



230=(2x)+x+(x-20)
We move all terms to the left:
230-((2x)+x+(x-20))=0
We calculate terms in parentheses: -(2x+x+(x-20)), so:
2x+x+(x-20)
We add all the numbers together, and all the variables
3x+(x-20)
We get rid of parentheses
3x+x-20
We add all the numbers together, and all the variables
4x-20
Back to the equation:
-(4x-20)
We get rid of parentheses
-4x+20+230=0
We add all the numbers together, and all the variables
-4x+250=0
We move all terms containing x to the left, all other terms to the right
-4x=-250
x=-250/-4
x=62+1/2

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