4(5t-6)=27t+7

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Solution for 4(5t-6)=27t+7 equation: 



4(5t-6)=27t+7

We move all terms to the left:

4(5t-6)-(27t+7)=0

We multiply parentheses

20t-(27t+7)-24=0

We get rid of parentheses

20t-27t-7-24=0

We add all the numbers together, and all the variables

-7t-31=0

We move all terms containing t to the left, all other terms to the right

-7t=31

t=31/-7

t=-4+3/7

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