4x-5(2x+1)=5+2(5x-21)

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Solution for 4x-5(2x+1)=5+2(5x-21) equation: 



4x-5(2x+1)=5+2(5x-21)

We move all terms to the left:

4x-5(2x+1)-(5+2(5x-21))=0

We multiply parentheses

4x-10x-(5+2(5x-21))-5=0



We calculate terms in parentheses: -(5+2(5x-21)), so:

5+2(5x-21)

determiningTheFunctionDomain
2(5x-21)+5

We multiply parentheses

10x-42+5

We add all the numbers together, and all the variables

10x-37

Back to the equation:

-(10x-37)



We add all the numbers together, and all the variables

-6x-(10x-37)-5=0

We get rid of parentheses

-6x-10x+37-5=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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