3x-3(2x-8)=3(3x-8)+7x

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Solution for 3x-3(2x-8)=3(3x-8)+7x equation: 



3x-3(2x-8)=3(3x-8)+7x

We move all terms to the left:

3x-3(2x-8)-(3(3x-8)+7x)=0

We multiply parentheses

3x-6x-(3(3x-8)+7x)+24=0



We calculate terms in parentheses: -(3(3x-8)+7x), so:

3(3x-8)+7x

We add all the numbers together, and all the variables

7x+3(3x-8)

We multiply parentheses

7x+9x-24

We add all the numbers together, and all the variables

16x-24

Back to the equation:

-(16x-24)



We add all the numbers together, and all the variables

-3x-(16x-24)+24=0

We get rid of parentheses

-3x-16x+24+24=0

We add all the numbers together, and all the variables

-19x+48=0

We move all terms containing x to the left, all other terms to the right

-19x=-48

x=-48/-19

x=2+10/19

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