108=8(2b+3)+5b

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Solution for 108=8(2b+3)+5b equation:



108=8(2b+3)+5b
We move all terms to the left:
108-(8(2b+3)+5b)=0
We calculate terms in parentheses: -(8(2b+3)+5b), so:
8(2b+3)+5b
We add all the numbers together, and all the variables
5b+8(2b+3)
We multiply parentheses
5b+16b+24
We add all the numbers together, and all the variables
21b+24
Back to the equation:
-(21b+24)
We get rid of parentheses
-21b-24+108=0
We add all the numbers together, and all the variables
-21b+84=0
We move all terms containing b to the left, all other terms to the right
-21b=-84
b=-84/-21
b=+4

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