4x-3(20-x)=6x-7(10x)-2(2x-5)

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Solution for 4x-3(20-x)=6x-7(10x)-2(2x-5) equation: 



4x-3(20-x)=6x-7(10x)-2(2x-5)

We move all terms to the left:

4x-3(20-x)-(6x-7(10x)-2(2x-5))=0

We add all the numbers together, and all the variables

4x-3(-1x+20)-(6x-710x-2(2x-5))=0

We multiply parentheses

4x+3x-(6x-710x-2(2x-5))-60=0



We calculate terms in parentheses: -(6x-710x-2(2x-5)), so:

6x-710x-2(2x-5)

We add all the numbers together, and all the variables

-704x-2(2x-5)

We multiply parentheses

-704x-4x+10

We add all the numbers together, and all the variables

-708x+10

Back to the equation:

-(-708x+10)



We add all the numbers together, and all the variables

7x-(-708x+10)-60=0

We get rid of parentheses

7x+708x-10-60=0

We add all the numbers together, and all the variables

715x-70=0

We move all terms containing x to the left, all other terms to the right

715x=70

x=70/715

x=14/143

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