9x2-36x+6=0

Solution for 9x2-36x+6=0 equation:

9x^2-36x+6=0

a = 9; b = -36; c = +6;
Δ = b2-4ac
Δ = -362-4·9·6
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{30}}{2*9}=\frac{36-6\sqrt{30}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{30}}{2*9}=\frac{36+6\sqrt{30}}{18}
$