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(2x+32/5)=(5x-4/5
We move all terms to the left:
(2x+32/5)-((5x-4/5)=0
We add all the numbers together, and all the variables
(+2x+32/5)-((+5x-4/5)=0
We get rid of parentheses
2x-((+5x-4/5)+32/5=0
We can not solve this equation
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