4x-1/5x+2=6

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Solution for 4x-1/5x+2=6 equation:



4x-1/5x+2=6
We move all terms to the left:
4x-1/5x+2-(6)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We add all the numbers together, and all the variables
4x-1/5x-4=0
We multiply all the terms by the denominator
4x*5x-4*5x-1=0
Wy multiply elements
20x^2-20x-1=0
a = 20; b = -20; c = -1;
Δ = b2-4ac
Δ = -202-4·20·(-1)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{30}}{2*20}=\frac{20-4\sqrt{30}}{40} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{30}}{2*20}=\frac{20+4\sqrt{30}}{40} $

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