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3/5x+24=x
We move all terms to the left:
3/5x+24-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+3/5x+24=0
We multiply all the terms by the denominator
-1x*5x+24*5x+3=0
Wy multiply elements
-5x^2+120x+3=0
a = -5; b = 120; c = +3;
Δ = b2-4ac
Δ = 1202-4·(-5)·3
Δ = 14460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14460}=\sqrt{4*3615}=\sqrt{4}*\sqrt{3615}=2\sqrt{3615}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-2\sqrt{3615}}{2*-5}=\frac{-120-2\sqrt{3615}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+2\sqrt{3615}}{2*-5}=\frac{-120+2\sqrt{3615}}{-10} $
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