4x-(47-6x)=4(2x-10)

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Solution for 4x-(47-6x)=4(2x-10) equation:



4x-(47-6x)=4(2x-10)
We move all terms to the left:
4x-(47-6x)-(4(2x-10))=0
We add all the numbers together, and all the variables
4x-(-6x+47)-(4(2x-10))=0
We get rid of parentheses
4x+6x-(4(2x-10))-47=0
We calculate terms in parentheses: -(4(2x-10)), so:
4(2x-10)
We multiply parentheses
8x-40
Back to the equation:
-(8x-40)
We add all the numbers together, and all the variables
10x-(8x-40)-47=0
We get rid of parentheses
10x-8x+40-47=0
We add all the numbers together, and all the variables
2x-7=0
We move all terms containing x to the left, all other terms to the right
2x=7
x=7/2
x=3+1/2

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