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4x^2=47x+126
We move all terms to the left:
4x^2-(47x+126)=0
We get rid of parentheses
4x^2-47x-126=0
a = 4; b = -47; c = -126;
Δ = b2-4ac
Δ = -472-4·4·(-126)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-65}{2*4}=\frac{-18}{8} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+65}{2*4}=\frac{112}{8} =14 $
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