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2/3(2x+2)+4=1/6(5x+29)
We move all terms to the left:
2/3(2x+2)+4-(1/6(5x+29))=0
Domain of the equation: 3(2x+2)!=0
x∈R
Domain of the equation: 6(5x+29))!=0We calculate fractions
x∈R
(12x5/(3(2x+2)*6(5x+29)))+(-3x2/(3(2x+2)*6(5x+29)))+4=0
We calculate terms in parentheses: +(12x5/(3(2x+2)*6(5x+29))), so:
12x5/(3(2x+2)*6(5x+29))
We multiply all the terms by the denominator
12x5
We add all the numbers together, and all the variables
12x^5
We do not support expression: x^5
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