4x-(2-2x)=3(3x+2)

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Solution for 4x-(2-2x)=3(3x+2) equation: 



4x-(2-2x)=3(3x+2)

We move all terms to the left:

4x-(2-2x)-(3(3x+2))=0

We add all the numbers together, and all the variables

4x-(-2x+2)-(3(3x+2))=0

We get rid of parentheses

4x+2x-(3(3x+2))-2=0



We calculate terms in parentheses: -(3(3x+2)), so:

3(3x+2)

We multiply parentheses

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

6x-(9x+6)-2=0

We get rid of parentheses

6x-9x-6-2=0

We add all the numbers together, and all the variables

-3x-8=0

We move all terms containing x to the left, all other terms to the right

-3x=8

x=8/-3

x=-2+2/3

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