1/3(x+3)=1/5(x-2)

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Solution for 1/3(x+3)=1/5(x-2) equation: 



1/3(x+3)=1/5(x-2)

We move all terms to the left:

1/3(x+3)-(1/5(x-2))=0



Domain of the equation: 3(x+3)!=0

x∈R





Domain of the equation: 5(x-2))!=0

x∈R



We calculate fractions


(5xx/(3(x+3)*5(x-2)))+(-3xx/(3(x+3)*5(x-2)))=0



We calculate terms in parentheses: +(5xx/(3(x+3)*5(x-2))), so:

5xx/(3(x+3)*5(x-2))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-3xx/(3(x+3)*5(x-2))), so:

-3xx/(3(x+3)*5(x-2))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

5xx-3xx=0

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