3(b-2)+5=7+3(2b-5)

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Solution for 3(b-2)+5=7+3(2b-5) equation: 



3(b-2)+5=7+3(2b-5)

We move all terms to the left:

3(b-2)+5-(7+3(2b-5))=0

We multiply parentheses

3b-(7+3(2b-5))-6+5=0



We calculate terms in parentheses: -(7+3(2b-5)), so:

7+3(2b-5)

determiningTheFunctionDomain
3(2b-5)+7

We multiply parentheses

6b-15+7

We add all the numbers together, and all the variables

6b-8

Back to the equation:

-(6b-8)



We add all the numbers together, and all the variables

3b-(6b-8)-1=0

We get rid of parentheses

3b-6b+8-1=0

We add all the numbers together, and all the variables

-3b+7=0

We move all terms containing b to the left, all other terms to the right

-3b=-7

b=-7/-3

b=2+1/3

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