4x+6=3(x-4)+15

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Solution for 4x+6=3(x-4)+15 equation: 



4x+6=3(x-4)+15

We move all terms to the left:

4x+6-(3(x-4)+15)=0



We calculate terms in parentheses: -(3(x-4)+15), so:

3(x-4)+15

We multiply parentheses

3x-12+15

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

4x-3x-3+6=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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