x-2(X-1)+3(X-2)+2(x-6)=0

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Solution for x-2(X-1)+3(X-2)+2(x-6)=0 equation: 



x-2(x-1)+3(x-2)+2(x-6)=0

We multiply parentheses

x-2x+3x+2x+2-6-12=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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