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x(11x-2)=11
We move all terms to the left:
x(11x-2)-(11)=0
We multiply parentheses
11x^2-2x-11=0
a = 11; b = -2; c = -11;
Δ = b2-4ac
Δ = -22-4·11·(-11)
Δ = 488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{488}=\sqrt{4*122}=\sqrt{4}*\sqrt{122}=2\sqrt{122}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{122}}{2*11}=\frac{2-2\sqrt{122}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{122}}{2*11}=\frac{2+2\sqrt{122}}{22} $
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