4x+50=(x+30)+(3x+60)+(2x-30)

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Solution for 4x+50=(x+30)+(3x+60)+(2x-30) equation: 



4x+50=(x+30)+(3x+60)+(2x-30)

We move all terms to the left:

4x+50-((x+30)+(3x+60)+(2x-30))=0



We calculate terms in parentheses: -((x+30)+(3x+60)+(2x-30)), so:

(x+30)+(3x+60)+(2x-30)

We get rid of parentheses

x+3x+2x+30+60-30

We add all the numbers together, and all the variables

6x+60

Back to the equation:

-(6x+60)



We get rid of parentheses

4x-6x-60+50=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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