6(3y+10)=2(12y-20)

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Solution for 6(3y+10)=2(12y-20) equation: 



6(3y+10)=2(12y-20)

We move all terms to the left:

6(3y+10)-(2(12y-20))=0

We multiply parentheses

18y-(2(12y-20))+60=0



We calculate terms in parentheses: -(2(12y-20)), so:

2(12y-20)

We multiply parentheses

24y-40

Back to the equation:

-(24y-40)



We get rid of parentheses

18y-24y+40+60=0

We add all the numbers together, and all the variables

-6y+100=0

We move all terms containing y to the left, all other terms to the right

-6y=-100

y=-100/-6

y=16+2/3

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