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5x(x+3)=3+2(2x-6)
We move all terms to the left:
5x(x+3)-(3+2(2x-6))=0
We multiply parentheses
5x^2+15x-(3+2(2x-6))=0
We calculate terms in parentheses: -(3+2(2x-6)), so:We get rid of parentheses
3+2(2x-6)
determiningTheFunctionDomain 2(2x-6)+3
We multiply parentheses
4x-12+3
We add all the numbers together, and all the variables
4x-9
Back to the equation:
-(4x-9)
5x^2+15x-4x+9=0
We add all the numbers together, and all the variables
5x^2+11x+9=0
a = 5; b = 11; c = +9;
Δ = b2-4ac
Δ = 112-4·5·9
Δ = -59
Delta is less than zero, so there is no solution for the equation
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