4x+3(x-2)=41

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Solution for 4x+3(x-2)=41 equation: 



4x+3(x-2)=41

We move all terms to the left:

4x+3(x-2)-(41)=0

We multiply parentheses

4x+3x-6-41=0

We add all the numbers together, and all the variables

7x-47=0

We move all terms containing x to the left, all other terms to the right

7x=47

x=47/7

x=6+5/7

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