3x+35=(7/2)x-5

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Solution for 3x+35=(7/2)x-5 equation: 



3x+35=(7/2)x-5

We move all terms to the left:

3x+35-((7/2)x-5)=0



Domain of the equation: 2)x-5)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x-((+7/2)x-5)+35=0

We multiply all the terms by the denominator


3x*2)x-5)-((+35*2)x-5)+7=0

We add all the numbers together, and all the variables

3x*2)x-5)-(70x-5)+7=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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